p-Block elementsHard
Question
In [Cr(O2)(NH3)4H2O]Cl2 ; oxidation number of Cr is + 3, then oxygen will be in the form :-
Options
A.Dioxo
B.Peroxo
C.Superoxo
D.Oxo
Solution
Let the oxidation number of oxygen is x
+ 3 + 2x + 0 x 4 + 0 - 2 = 0
2x + 1 = 0 ⇒ 2x = - 1 [x = - 1/2]
Thus, oxygen will be in superoxoform
+ 3 + 2x + 0 x 4 + 0 - 2 = 0
2x + 1 = 0 ⇒ 2x = - 1 [x = - 1/2]
Thus, oxygen will be in superoxoform
Create a free account to view solution
View Solution FreeMore p-Block elements Questions
Which of the following product(s) is/are obtained when Cl2O6 reacts with KOH ?...A colourless gas which burns with blue flame and reduces CuO to Cu is :...Carbon monoxide is prepared by :...Which of the following facts regarding boron and silicon is true ?...Thermodynamically the most stable form of carbon is :...