SolutionHard

Question

An electrolysis cell contains a solution of Ag2SO4 and has platinum electrodes. A current is passed until 1.6 gm of O2 has been liberated at anode. The amount of silver deposited at cathode will be:-

Options

A.108 gm
B.1.6 gm
C.0.8 gm
D.21.60 gm

Solution



⇒ WAy = 0.2 × 108
= 21.6 gm

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