GravitationHard
Question
A simple pendulum has a time period T1 when on the earth′s surface and T2 when taken to a height R above the earth′s surface, where R is the radius of the earth. The value of T2 / T1 is
Options
A.1
B.√2
C.4
D.2
Solution
T = 
i.e., 
= 
where g1 = acceleration due to graity on earth’s surface = g
g2 = acceleration due to gravity at a height h = R from earth′s surface = g/4
i.e., = where g1 = acceleration due to graity on earth’s surface = g
g2 = acceleration due to gravity at a height h = R from earth′s surface = g/4
Create a free account to view solution
View Solution FreeMore Gravitation Questions
Gravitional mass is proportional to the gravitational :...Suppose a smooth tunnel is dug along a straight line joining two points on the surface of the Earth and a particle is dr...Calculate the mass of the sun if the mean radius of the earth′s orbit is 1.5 × 108 km and G = 6.67 × 10-...The condition for a uniform spherical mass m of radius r to be a black hole is :[G =gravitational constant and g = accel...There are two bodies of masses 100 kg and 10000 kg separated by a distance 1 m. At whatdistance from the smaller body, t...