GravitationHard
Question
One projectile after deviating from its path starts moving round the Earth in a circular path of radius equal to nine times the radius of Earth R. Its period will be : -
Options
A.2π
B.27 × 2π
C.π
D.0.8 × 3π
Solution
Net force towards the centre ⇒ mω2(9R) =
⇒ ω2 =
⇒ T =
⇒ 27 × 2π
⇒ ω2 =
Create a free account to view solution
View Solution FreeMore Gravitation Questions
Imagine a light planet revolving around a very massivr star in a circular orbit of radius R with a period of revolution ...The magnitudes of the gravitational field at distance r1 and r2 from the centre of a uniform, sphere of radius R and M a...Find the distance between centre of gravity and centre of mass of a two particle system attached to the ends of a light ...A mass m is placed in the cavity inside a hollow sphere of mass M as shown in the figure. What is the gravitational forc...A particle of mass m is upwards from the surface of the earth, with a velocity u. The mass and the radius of the earth a...