Chemical EquilibriumHard
Question
XY2 dissociates as :
XY2(g) ⇋ XY(g) + Y(g)
initial pressure of XY2 is 600 mm Hg. The total pressure at equilibrium is 800 mm Hg. Assuming volume of system to remain constant, the value of Kp is :-
XY2(g) ⇋ XY(g) + Y(g)
initial pressure of XY2 is 600 mm Hg. The total pressure at equilibrium is 800 mm Hg. Assuming volume of system to remain constant, the value of Kp is :-
Options
A.50
B.100
C.200
D.400
Solution
XY2(g) ⇋ XY(g) + Y(g)
600 0 0 Initially
600-P P P at equilibrium
given 600 - P + P + P = 800
P = 200 mm of Hg
KP =
= 100
600 0 0 Initially
600-P P P at equilibrium
given 600 - P + P + P = 800
P = 200 mm of Hg
KP =
= 100Create a free account to view solution
View Solution FreeMore Chemical Equilibrium Questions
The equilibrium mixture for the reaction 2H2S(g)$\rightleftharpoons$ 2H2(g) + S2(g) has 1 mole of H2S, 0.20 mole of H2 a...For the equilibrium SrCl2·6H2O(s) $\rightleftharpoons$SrCl2·2H2O(s) + 4H2O(g), KP = 8.1 × 10−7 atm4 at 27oC. If 1.642 L ...Solubility of a solute in a solvent (say, water) is dependent on the temperature as given by S = A.e–ΔH/RT, where ΔH is ...Which of the following statements is correct for a reversible process in a state of equilibrium ?...PCl5(g) $\rightleftharpoons$PCl3(g) + Cl2(g). In the above reaction, the partial pressure of PCl3, Cl2 and PCl5 are 0.3,...