Chemical EquilibriumEasy
Question
XY2 dissociates as :
XY2(g) ⇋ XY(g) + Y(g)
initial pressure of XY2 is 600 mm Hg. The total pressure at equilibrium is 800 mm Hg. Assuming volume of system to remain constant, the value of Kp is :-
XY2(g) ⇋ XY(g) + Y(g)
initial pressure of XY2 is 600 mm Hg. The total pressure at equilibrium is 800 mm Hg. Assuming volume of system to remain constant, the value of Kp is :-
Options
A.50
B.100
C.200
D.400
Solution
XY2(g) ⇋ XY(g) + Y(g)
600 0 0 Initially
600-P P P at equilibrium
given 600 - P + P + P = 800
P = 200 mm of Hg
KP =
= 100
600 0 0 Initially
600-P P P at equilibrium
given 600 - P + P + P = 800
P = 200 mm of Hg
KP =
= 100Create a free account to view solution
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