ElectrostaticsEasy
Question
ABC is a right angle triangle with right angle A and AB = AC = 30 cm if the charge on B and C is 4 × 10-3 μC then electric field at A will be :-
Options
A.400 N/C parallel to BC
B.800 N/C parallel to BC
C.400 √2 N/C perpendicular to BC
D.800 N/C perpendicular to BC
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