Wave motionHard
Question
In Melde′s experiment, the string vibrates in 4 loops when a 50 gm weight is placed in the pan of weight 15 gm. To make the string to vibrates in 6 loops the weight that has to be removed from the pan is :-
Options
A.0.0007 Kg-wt
B.0.0021 Kg-wt
C.0.036 Kg-wt
D.0.0029 Kg-wt
Solution
n = 
⇒ P √T = constant (2l/P = λ)
⇒ T2 = 28.88 gm-wt
T1 - T2 = 65 - 28.88 = 36.12 gm-wt = 0.036 kg-wt
⇒ P √T = constant (2l/P = λ)⇒ T2 = 28.88 gm-wt
T1 - T2 = 65 - 28.88 = 36.12 gm-wt = 0.036 kg-wt
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