Wave motionEasy
Question
An object of spcific gravity ρ is hung from a thin steel wire. he findamental frequency for transervse standing waves in the wire is 300 Hz. The object is immersed in water, so that one half of its volume is submerged. The new fundamental frequency (in Hz) is
Options
A.

B.

C.

D.

Solution

The diagramatic representation of the given problem is shown in figure. The expression of fundamental frequency is

In air T = mg = (Vρ)g
∴
.......(i)When the object is half immersed in water
T′ = mg - upthrust = Vρg -
g(2ρ - ρw)The new fundamental frequency is
v′ =
.....(ii)∴

or v′ = v

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