Chemical EquilibriumHardBloom L2
Question
When two reactants $A$ and $B$ are mixed to give products $C$ and $D$, the reaction quotient $Q$ at the initial stage of the reaction is:
Options
A.Zero
B.Decreasing with time
C.Independent of time
D.Increasing with time
Solution
**Given:** Reaction: $A + B \rightarrow C + D$
**Formula:**
$$Q = \frac{[C][D]}{[A][B]}$$
**At $t = 0$ (initial stage):**
No products have formed yet, so $[C] = 0$ and $[D] = 0$.
$$Q = \frac{0 \times 0}{[A][B]} = 0$$
This confirms option **(A)**.
**As the reaction proceeds ($t > 0$):**
Concentrations of $C$ and $D$ increase, while concentrations of $A$ and $B$ decrease. Therefore, $Q$ increases with time until $Q = K_c$ at equilibrium.
This confirms option **(D)**.
**Answer: (A) and (D)**
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