Ionic EquilibriumMedium
Question
At 90oC, pure water has [H3O+] as 10-6 mol -1. What is the value of Kw at 90oC ?
Options
A.10-6
B.10-12
C.10-14
D.10-8
Solution
Kw = [H+][OH-]
In pure water [H+] = [OH-]
At 90oC, given that [H+] = 10-6 mol L-1
and [OH-] = 10-6 mol L-6
∴ Kw = [10-6]2 = 10-2
In pure water [H+] = [OH-]
At 90oC, given that [H+] = 10-6 mol L-1
and [OH-] = 10-6 mol L-6
∴ Kw = [10-6]2 = 10-2
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