Mole ConceptHard
Question
112.0 mL of NO2 at STP was liquefied, the density of the liquid being 1.15 g mL-1. Calculate the volume of and the number of molecules in the liquid NO2 . (At. wt. N = 14)
Options
A.0.10 mL and 3.01 × 1022
B.0.20 mL and 3.01 × 1021
C.0.20 mL and 6.02 × 1023
D.0.40 mL and 6.02 × 1021
Solution
Mole of NO2 = 
= 5 × 10-3
Mass of NO2 = 5 × 10-3 × 46 = 0.23 gm
Volume of NO2 =
= 0.2 ml
Number of molecule = 5 × 10-3 × 6.023 × 1023 = 3.1 × 1021.
= 5 × 10-3 Mass of NO2 = 5 × 10-3 × 46 = 0.23 gm
Volume of NO2 =
= 0.2 mlNumber of molecule = 5 × 10-3 × 6.023 × 1023 = 3.1 × 1021.
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