ThermochemistryHard
Question
Reaction involving gold have been of particular intersect to alchemists. Consider the following reactions,
Au(OH)3 + 4 HCl HAuCl4 + 3H2O, áƒH = - 28 kcal
Au(OH)3 + 4 HBr HAuBr4 + 3H2O, áƒH = - 36.8 kcal
In an experiment there was an absorption of 0.44 kcal when one mole of HAuBr4 was mixed with 4 moles of HCl. What is the percentage conversion of HAuBr4 into HAuCl4 ?
Options
A.0.5%
B.0.6%
C.5%
D.50%
Solution
HAuBr4 + 4HCl HAuCl4 + 4HBr
         áƒH = - 28 + 36.8
             = 8.8 kcal
% converssion is
× 100 = 5.
         áƒH = - 28 + 36.8
             = 8.8 kcal
% converssion is
× 100 = 5.Create a free account to view solution
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