ThermochemistryHard
Question
The enthalpies of neutralization of a weak base AOH and a strong base BOH by HCI are -12250 cal/ mol and -13000 cal/ mol respecitively. When one mole of HCI is added to a solution containing 1 mole of AOH and 1 mole of BOH, the enthalpy change was -12500 cal/ mol. In what ratio the acid is distributed between AOH and BOH?
Options
A.2 : 1
B.2 : 3
C.1 : 2
D.None of these
Solution
-12250x -13000 (1 - x) = - 12500
750 x = 500 ⇒ x = 2/3
So, required ratio is = 2/14
750 x = 500 ⇒ x = 2/3
So, required ratio is = 2/14
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