ThermochemistryHard
Question
The enthalpies of neutralization of a weak base AOH and a strong base BOH by HCI are -12250 cal/ mol and -13000 cal/ mol respecitively. When one mole of HCI is added to a solution containing 1 mole of AOH and 1 mole of BOH, the enthalpy change was -12500 cal/ mol. In what ratio the acid is distributed between AOH and BOH?
Options
A.2 : 1
B.2 : 3
C.1 : 2
D.None of these
Solution
-12250x -13000 (1 - x) = - 12500
750 x = 500 ⇒ x = 2/3
So, required ratio is = 2/14
750 x = 500 ⇒ x = 2/3
So, required ratio is = 2/14
Create a free account to view solution
View Solution FreeMore Thermochemistry Questions
ᐃHfo(298K) of methanol is given by the chemical equation :...The enthalpy change of a reaction does not depend on :...CsF(S) → Cs+(aq) + F-(aq) ᐃH = - 40 kJ mol- If lattic energy of CsF is 750 kJ mol- . Then the summation of h...A heat engine is operating between 500K to 400K. If the engine absorbs 100J heat, then which of the following is impossi...If the enthalpy of formation and enthalpy of solution of HCl (g) are - 92.3 kJ/mol and - 75.14 kJ/mol respectively then ...