Chemical EquilibriumHard
Question
For the equilibrium CuSO4.5H2O(s) ⇋ CuSO4.3H2O(s) + 2H2O(g)
Kp = 2.25 × 10-4 atm2 and vapour pressure of water is 22.8 Torr at 298 K.
CuSO4.5H2O(s) is efflorescent (i.e., loses water) when relative humidity is :
Kp = 2.25 × 10-4 atm2 and vapour pressure of water is 22.8 Torr at 298 K.
CuSO4.5H2O(s) is efflorescent (i.e., loses water) when relative humidity is :
Options
A.less than 33.3%
B.less than 50 %
C.less than 66.6%
D.above 66.6%
Solution
CuSO4 . 5H2O(s) ⇋ CuSO4 . 3H2O(s) + 2H2O(g) KP = 2.25 × 10-4
KP = P2H2O = 2.25 × 10-4 PH2O = 1.5 × 10-2
Vapour Pr =
= 3 × 10-2 R.H. = 
× 100 = 50%
Therefore, (B) option is correct.
KP = P2H2O = 2.25 × 10-4 PH2O = 1.5 × 10-2
Vapour Pr =
= 3 × 10-2 R.H. = × 100 = 50%Therefore, (B) option is correct.
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