Atomic StructureHard
Question
Which of the following statement (s) is (are) correct ?
Options
A.The electroni configuration of Cr is [Ar] 3d54s1 (Atomic number of Cr = 24)
B.The magnetic quantm number may have a negative value
C.In silver atom 23 electrons have a spin of one type and 24 of the opposite type (Atomic number of Ag = 27)
D.The oxidation state of nitrogen in HN3 is
Solution
(a) 24Cr = [Ar]3d5, 4s1
(b) m = - l to + l including zero.
(c) 47Ag = 1s2, 2s2, 2p6 3s2, 3p6, 3d10, 4s2, 4sp6, 4d10, 5s1
Thus 24 electron have s = +
while rest 23 have. s = -
(d) Oxidation number of N in NH3 is -
(b) m = - l to + l including zero.
(c) 47Ag = 1s2, 2s2, 2p6 3s2, 3p6, 3d10, 4s2, 4sp6, 4d10, 5s1
Thus 24 electron have s = +
while rest 23 have. s = - (d) Oxidation number of N in NH3 is -
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
The potential energy of electron revolving in the ground state of H atom is...Which of the following will not change if the choice of the zero potential energy is changed in Bohr model -...How much distance an electron revolving in 3rd orbit of He+ ion will travel in one second...For principle quantum number n = 4, the total number of orbitals having l = 3 is :...Maximum number of electrons in a subshell with l = 3 and n = 4 is...