Atomic StructureHard
Question
Which of the following statement (s) is (are) correct ?
Options
A.The electroni configuration of Cr is [Ar] 3d54s1 (Atomic number of Cr = 24)
B.The magnetic quantm number may have a negative value
C.In silver atom 23 electrons have a spin of one type and 24 of the opposite type (Atomic number of Ag = 27)
D.The oxidation state of nitrogen in HN3 is
Solution
(a) 24Cr = [Ar]3d5, 4s1
(b) m = - l to + l including zero.
(c) 47Ag = 1s2, 2s2, 2p6 3s2, 3p6, 3d10, 4s2, 4sp6, 4d10, 5s1
Thus 24 electron have s = +
while rest 23 have. s = -
(d) Oxidation number of N in NH3 is -
(b) m = - l to + l including zero.
(c) 47Ag = 1s2, 2s2, 2p6 3s2, 3p6, 3d10, 4s2, 4sp6, 4d10, 5s1
Thus 24 electron have s = +
while rest 23 have. s = - (d) Oxidation number of N in NH3 is -
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
The number of radial nodes of 3s, 3p and 3d electrons are, respectively,...For which atom or ion, the energy level of the second excited state is −13.6 eV?...The wave numbers of three spectral lines of $H$ atom are considered. Identify the set of spectral lines belonging to Bal...Uncertainty in position is twice the uncertainty in momentum. Uncertainty in velocity is :...A sample of hydrogen atoms in ground state is exposed to electromagnetic radiations of 1028 Å. The wavelengths of the in...