Coordination CompoundHard
Question
Which of the following is/are inner orbital complexes as well as paramagnetic with magnetic moment equal to 3.78 (approximate)?
Options
A. [Co(ox)3]3-
B.[Cr(NH3)6]3+
C.[Fe(H2O)5NO]2+
D.[Zn(NH3)6]2+
Solution
(A) [Co(ox)3]3- ; 3d6 configuration, all electrons are paired and hybridisation is d2sp3 -diamagnetic with m = 0.
(B) [Cr(NH3)6]3+ ; 3d3 configuration, all electrons are unpaired and paramagnetic with μ(approximately)3.78 B.M and hybridisaion is d2sp3 (NH3 strong field ligand).
(C) [Fe(H2O)5NO]2+ ; 3d6 4s1 configuration, hybridisation is sp3d2 and is paramagnetic with three unpaired electrons (μ ≈ 3.78 B.M.)
(D) [Zn(NH3)6]2+ ; 3d10 configuration, all electrons are paired so diamagnetic with m = 0 and hybridisation is sp3d2.
(B) [Cr(NH3)6]3+ ; 3d3 configuration, all electrons are unpaired and paramagnetic with μ(approximately)3.78 B.M and hybridisaion is d2sp3 (NH3 strong field ligand).
(C) [Fe(H2O)5NO]2+ ; 3d6 4s1 configuration, hybridisation is sp3d2 and is paramagnetic with three unpaired electrons (μ ≈ 3.78 B.M.)
(D) [Zn(NH3)6]2+ ; 3d10 configuration, all electrons are paired so diamagnetic with m = 0 and hybridisation is sp3d2.
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