Coordination CompoundHard

Question

What is the charge on the complex [Cr(C2O4)2(H2O)2] formed by Cr(III) ?

Options

A.+3
B.+1
C.+2
D.-1

Solution

H2O is neutral, chromium oxidation state i.e. charge is +3 and oxalato anion has -2 charge; due to two C2O42- it will be -4 and net charge on the complex is algebraic sum of the charge on metal ion and ligands present in the coordination sphere. So   3 + 2 × (-2) = -1. So the formulae of complex is [Cr(C2O4)(H2O)]-.

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