Coordination CompoundHard
Question
Consider the following statements
S1 : [ Cr (NH3)6]3+ is a inner orbital complex with crystal field stabilization energy equal to - 1.2 Do
S2 : The complex formed by joining the CN- ligands to Fe3+ ion has theoretical value of ′spin only′ magnetic moment equal to 1.73 B.M.
S3 : Na2S + Na2 [Fe (CN)5 NO] → Na4 [ Fe (CN)5 NOS], In reactant and product the oxidation states of iron are sameand arrange in the order of true/false.
S1 : [ Cr (NH3)6]3+ is a inner orbital complex with crystal field stabilization energy equal to - 1.2 Do
S2 : The complex formed by joining the CN- ligands to Fe3+ ion has theoretical value of ′spin only′ magnetic moment equal to 1.73 B.M.
S3 : Na2S + Na2 [Fe (CN)5 NO] → Na4 [ Fe (CN)5 NOS], In reactant and product the oxidation states of iron are sameand arrange in the order of true/false.
Options
A.F T F
B.T T F
C.T T T
D.F F F
Solution
S1 : Cr3+ 
CFSE = 3 × - 0.4 = - 1.2 ᐃ0, hybridisation is d2sp3 (NH3 is strong ligand)
S2 : Fe3+, 3d5 - one unpaired electron after pairing (CN- is stronger field ligand)
∴ μ =
≈ 1.73 BM
S3 : [FeII(CN-5)5NO+]2- and [FeII(CN-5)5NOS-1]1-
In reactant and product, the iron is in same oxidation state i.e. +2.
CFSE = 3 × - 0.4 = - 1.2 ᐃ0, hybridisation is d2sp3 (NH3 is strong ligand)S2 : Fe3+, 3d5 - one unpaired electron after pairing (CN- is stronger field ligand)
∴ μ =
≈ 1.73 BMS3 : [FeII(CN-5)5NO+]2- and [FeII(CN-5)5NOS-1]1-
In reactant and product, the iron is in same oxidation state i.e. +2.
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