Photoelectric EffectMedium
Question
The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface, having work function of 5.01 eV, when ultraviolet light of 200 nm falls on it, must be
Options
A.2.4 V
B.- 1.2 V
C.- 2.4 V
D.- 1.2 V
Solution
Here,
Incident wavelength, λ = 200nm
Work function, φ0 = 5.10eV
According to Einstein’s photoelectric equation
eVs =
eVs =
- φ0
where Vs is the stopping potential
eVs =
- 5.01 eV
6.2 eV - 5.01 eV = 1.2 V
The potential difference that must be appiled to stop photoelectrons = - Vs = - 1.2 V.
Incident wavelength, λ = 200nm
Work function, φ0 = 5.10eV
According to Einstein’s photoelectric equation
eVs =
eVs =
- φ0where Vs is the stopping potential
eVs =
- 5.01 eV6.2 eV - 5.01 eV = 1.2 V
The potential difference that must be appiled to stop photoelectrons = - Vs = - 1.2 V.
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