ElectroMagnetic InductionHard
Question
Power factor of an L - R series circuit is 0.6 and that of a C - R series circuit is 0.5 If the element (L, C, and R) of the two circuits are joined in series the power factor of this circuit is found to be 1. The ratio of the resistance in the L - R circuit to the resistance in the C - R circuit is
Options
A.
B.
C.
D.
Solution
For (L - R) circuit
cos θ =
⇒ θ = 53o ⇒ XL = 
R
For (C - R) circuit
cos θ =
⇒ θ = 60o ⇒ XC = √3 R2
In L - C - R power factor is i i.e. reactant is zero
XL = XC ⇒
R1 = √3R2 ⇒ 
cos θ =
⇒ θ = 53o ⇒ XL = RFor (C - R) circuit
cos θ =
⇒ θ = 60o ⇒ XC = √3 R2In L - C - R power factor is i i.e. reactant is zero
XL = XC ⇒
R1 = √3R2 ⇒ Create a free account to view solution
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