ElectroMagnetic InductionHard
Question
An LCR series circuit with 100 Ω resistance is connected to an AC source of 200 V and angular frequency 300 radians per second. When only the capacitance is removed, the current lags behind the voltage by 60o. When only the inductance is removed, the current leads the voltage by 60o. Then the current and power dissipated in LCR circuit are respectively
Options
A.1A, 200 watt.
B.1A, 400 watt.
C.2a, 200 watt.
D.2A, 400 watt.
Solution
tan 60o = 
Also tan 60o = 
is XC = XL = √3 R
series L-C-R is in resonating condition
I =
= 2A
P = I2R = 4 × 100 = 400W
Also tan 60o = is XC = XL = √3 Rseries L-C-R is in resonating condition
I =
= 2AP = I2R = 4 × 100 = 400W
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