Current Electricity and Electrical InstrumentHard
Question
A galvanometer has coil of resistance 100 ohm and gives a full scale defelection for 30 mA current. It is to work as a voltmeter of 30 volt range, the resistance required to be added will be
Options
A.900 Ω
B.1800 Ω
C.500 Ω
D.100 Ω
Solution

Here ,
Resistance of galvanometer, G = 100 Ω
Current for full scale deflection, Ig = 30mA = 30 × 10-03 A
Ragne of voltmeter V = 30 V
To convert the galvanometer into an voltmeter of a given range, a resistance R is connected in series with it as shown in the figure
From figure
V = Ig (G + R)
or =
- 100Ω= 1000 - 100 = 900
Create a free account to view solution
View Solution FreeTopic: Current Electricity and Electrical Instrument·Practice all Current Electricity and Electrical Instrument questions
More Current Electricity and Electrical Instrument Questions
The current voltage graph for a given metallic conductor at two different temperatures T1 and T2 are as shown in the fig...Two ideal batteries of emf V1 and V2 and three resistances R1, R2 and R3 are connected as shown in the figure. The curre...Identify which of the following diagrams represent the internal construction of the wound in a resistance box or PO box?...Three 60W, 120W light bulbs are connected across a 120 V power source. If resistance of each bulb does not change with c...In an a. c. circuit, the instantaneous e.m.f. and current are given by e = 100 sin 30 t i = 20 sin 30t-π4 In one cy...