ElectrostaticsHard

Question

At distance of 5cm and 10cm outwards from the surface of a uniformly charged solid sphere, the potentials are 100V and 75V respectively. Then :

Options

A.Potential at its surface is 150V.
B.The charge on the sphere is (5/3) × 10-9C.
C.The electric field on the surface is 1500 V/m.
D.The electric potential at its centre is 225V.

Solution

= 100 V    & =  75 V
∴    Q = ,  r = 10 cm
∴    Vsurface =  = 150V    Esurface = = 1500 V/m
Vcentre = Vsurface = × 150 = 225 V

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