ElectroMagnetic InductionHard
Question
For an LCR series circuit, phosphors of current i and applied voltage V = V0 sinωt are shown in diagram at t = 0. Which of the following is/are CORRECT ?
Options
A.At t = 
, instantaneous power supplied by source is negative.
, instantaneous power supplied by source is negative.B.From 0 < t < 
, average power supplied by source is positive.
, average power supplied by source is positive.C.At t = 
, instantaneous power supplied by source is negative.
, instantaneous power supplied by source is negative.D.If ω is increased slightly, angle between the two phosphors decreases.
Solution
The graph shows V & I as function of time. Current leads the voltage by π/3
Power is positive if V & I are of same sign. Power is negative if V & I are of opposite sign
If ω ↑ ⇒
thus angle decreases.
Power is positive if V & I are of same sign. Power is negative if V & I are of opposite sign
If ω ↑ ⇒
thus angle decreases.Create a free account to view solution
View Solution FreeMore ElectroMagnetic Induction Questions
The potential difference V and current I flowing through the AC circuit is given by V = 5 cos(ωt - π/6) volt a...An ac source of angular frequency ω is fed across a resistor R and a capacitor C in series. The current registered ...In a coil of self inductance of 5henry, the rate of change of current is 2 ampere per second, the e.m.f. induced in the ...The self inductance of a choke coil is 10 mH. when it is connected with it is connected with a 10 V D. C. source. source...In a series CR circuit shown in figure, the applied voltage is 10V and the voltage voltage across capacitor is found to ...