ElectroMagnetic InductionHard
Question
An induction coil stores 32 joules of magnetic energy and dissipates energy as heat at the rate of 320 watts. when a current of 4 amperes is passed through it. Find the time constant of the circuit when the coil is joined across a battery.
Options
A.0.02 s
B.0.1 s
C.0.3 s
D.0.4 s
Solution
u = 
LI2u ⇒ = 32 Joule
L = ?, I = 4A
L = 4H, P = i2R ⇒ R = 20 ohm
Time =
= 0.2 sec
LI2u ⇒ = 32 JouleL = ?, I = 4A
L = 4H, P = i2R ⇒ R = 20 ohm
Time =
= 0.2 secCreate a free account to view solution
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