ElectroMagnetic InductionHard
Question
An induction coil stores 32 joules of magnetic energy and dissipates energy as heat at the rate of 320 watts. when a current of 4 amperes is passed through it. Find the time constant of the circuit when the coil is joined across a battery.
Options
A.0.02 s
B.0.1 s
C.0.3 s
D.0.4 s
Solution
u = 
LI2u ⇒ = 32 Joule
L = ?, I = 4A
L = 4H, P = i2R ⇒ R = 20 ohm
Time =
= 0.2 sec
LI2u ⇒ = 32 JouleL = ?, I = 4A
L = 4H, P = i2R ⇒ R = 20 ohm
Time =
= 0.2 secCreate a free account to view solution
View Solution FreeMore ElectroMagnetic Induction Questions
A particle of mass m and charge q, moving with velocity V enters Region II normal to the boundary as shown in the figure...A long horizontal metallic rod with length along the east-west direction is falling under gravity. The potential differe...In a transformer 220A.C. voltage is increased to 2200 volts. If the number of turns in the secondary are 2000, then the ...In a coil of resistance of 10Ω, the induced current developed by changing magnetic flux through it,is shown in figu...A conductor loop of radius R is present in a uniform magnetic field B perpendicular the plane of the ring. If radius R v...