ElectroMagnetic InductionMedium
Question
An induction coil stores 32 joules of magnetic energy and dissipates energy as heat at the rate of 320 watts. when a current of 4 amperes is passed through it. Find the time constant of the circuit when the coil is joined across a battery.
Options
A.0.02 s
B.0.1 s
C.0.3 s
D.0.4 s
Solution
u = 
LI2u ⇒ = 32 Joule
L = ?, I = 4A
L = 4H, P = i2R ⇒ R = 20 ohm
Time =
= 0.2 sec
LI2u ⇒ = 32 JouleL = ?, I = 4A
L = 4H, P = i2R ⇒ R = 20 ohm
Time =
= 0.2 secCreate a free account to view solution
View Solution FreeMore ElectroMagnetic Induction Questions
A closed coil consists of 500 turns on a rectangular frame of area 4.0 cm2 and has a resistance of 50 ohms. The coil is ...A rectangular loop of sides ′a′ and ′b′ is placed in xy plane. A very long wire is also placed i...The magnetic field in a coil of 100 turns and 40 cm2 an area is increased from 1 tesla to 6 tesla in 2 second. The magne...In an AC generator, a coil with N turns, all of the same area A and total resistance R, rotates with frequency ω in...The voltage time (V - t) graph for triangle wave having peak value. V0 is as shown in figure : The rms value of V in tim...