ElectroMagnetic InductionHard
Question
An induction coil stores 32 joules of magnetic energy and dissipates energy as heat at the rate of 320 watts. when a current of 4 amperes is passed through it. Find the time constant of the circuit when the coil is joined across a battery.
Options
A.0.02 s
B.0.1 s
C.0.3 s
D.0.4 s
Solution
u = 
LI2u ⇒ = 32 Joule
L = ?, I = 4A
L = 4H, P = i2R ⇒ R = 20 ohm
Time =
= 0.2 sec
LI2u ⇒ = 32 JouleL = ?, I = 4A
L = 4H, P = i2R ⇒ R = 20 ohm
Time =
= 0.2 secCreate a free account to view solution
View Solution FreeMore ElectroMagnetic Induction Questions
A negative charge is given to a nonconducting loop and the loop is rotated in the plane of paper about its centre as sho...A particle of mass m and charge q, moving with velocity V enters Region II normal to the boundary as shown in the figure...Side of a square coil is 4 cm. A magnetic field normal to plane of coil is changing at a rate of 0.4 tesla/sec. If resis...Consider the situation shown in the figure. The wire AB is slide over two parallel rails with a constant velocity. If th...Two co-axial solenoids shown in figure. If key of primary suddenly opened then direction of instantaneous induced curren...