Rotational MotionHard
Question
A liquid in a beaker has temperature θ(t) at timet and θ0 is temperature of surroundings, thenaccording to Newton′s law of cooling thecorrect graph between loge (θ - θ0) and t is :-
Options
A.
B.
C.
D.
Solution
Rate of cooling 
On integrating
⇒ ln (θ - θ0) = - kt + C
⇒ correct answer will be (2)
On integrating
⇒ ln (θ - θ0) = - kt + C
⇒ correct answer will be (2)
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