Rotational MotionMedium
Question
A thin circular ring of mass M and radius ′r′ is rotating about its axis with a constant angular velocity ω. Four objects each of mass m, are kept gently to the opposite ends of two perpendicular diameters of the ring. The new angular velocity of the ring will be : -
Options
A.
B.
C.
D.
Solution
From angular moment conservation
Mr2 × ω = (M + 4m) r2 × ω′
Mr2 × ω = (M + 4m) r2 × ω′
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