Nuclear Physics and RadioactivityMedium
Question
The decay constant of radio isotope is λ. If A1 A2 are its activities at time t1 and t2 respectively, the number of nuclei which have decayed during the time (t1 - t2)
Options
A.A1t1 - A2t2
B.A1 - A2
C.(A1 - A2)/λ
D.λ(A1 - A2)
Solution
A1 = λ N1 at time t1
A2 = λ N2 at time t2
Therefore, number of nuclie decayed during time internal (t1 - t2) is
N1 - N2 =
A2 = λ N2 at time t2
Therefore, number of nuclie decayed during time internal (t1 - t2) is
N1 - N2 =

Create a free account to view solution
View Solution FreeMore Nuclear Physics and Radioactivity Questions
If the rate of energy emitted from a star is 4.5 × 1035 J/s, then the rate of loss of its mass will be-...Radius of which nucleus is half of radius of the nucleus Fe56 :-...Given below are two statements:Statement I: For all elements, greater the mass of the nucleus, greater is the binding en...Consider α- particle, β - particle and γ- particle each having an energy of 0.5 MeV. In increasing order ...Which of the following statements is correct?...