s-Block ElementsHard
Question
Potassium carbonate is not prepared by :
Options
A.Solvay process
B.Le-Blanc process
C.Prechts process
D.none of these.
Solution
(A) KHCO3 obtained as intermediate is water soluble. So it cannot be separated for obtaing K2CO3 by calcination in Solvay process.
(B) Le-Blanc process :
KCl + H2SO4 → KHSO4 + HCl ; KHSO4 + KCl → K2SO4 + HCl
K2SO4 + CaCO3 + 2C → K2CO3 + CaS + 2CO2
(C) Prechts process :
(a) 2KCl + 3(MgCO3. 3H2O) + CO2 → 2(Mg CO3. KHCO3. 4H2O) + MgCl2
(b) 2(MgCO3. KHCO3. 4H2O)
2Mg CO3 ↓ + K2CO3 + 9H2O + CO2.
(B) Le-Blanc process :
KCl + H2SO4 → KHSO4 + HCl ; KHSO4 + KCl → K2SO4 + HCl
K2SO4 + CaCO3 + 2C → K2CO3 + CaS + 2CO2
(C) Prechts process :
(a) 2KCl + 3(MgCO3. 3H2O) + CO2 → 2(Mg CO3. KHCO3. 4H2O) + MgCl2
(b) 2(MgCO3. KHCO3. 4H2O)
2Mg CO3 ↓ + K2CO3 + 9H2O + CO2. Create a free account to view solution
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