Magnetic field due to currentHard
Question
A charged particle of specific charge q is released from origin at time t = 0 with velocity 
= v0 (î + ĵ) in uniform magnetic field 
= B0î. Coordinates of the particle at time t = 
are
= v0 (î + ĵ) in uniform magnetic field = B0î. Coordinates of the particle at time t = areOptions
A.
B.
C.
D.
Solution
F = qV×B = qv0 (î + ĵ) × 
8; = (-) qv0B
T =
∴ ωt = 
= π
8; = (-) qv0BT =
∴ ωt = = πCharge will complete half circle
∴ X = v0t =
; Y = 0
Z = - 2R =
∴ X = v0t =
; Y = 0Z = - 2R =
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