Magnetic field due to currentHard
Question
A particle of charge per unit mass a is released from origin with velocity 
= v0î in a magnetic field 
= - B0
for x ≤ 
and = 0 for x > 
. The x-coordinates of the particle at time 
would be
= v0î in a magnetic field = - B0 for x ≤ and = 0 for x > . The x-coordinates of the particle at time would be Options
A.
B.
C.
D.
Solution
R sin θ = 
R ; θ = π/3
∴ x - coordinate
=
R + v0 cos θ
=
R ; θ = π/3∴ x - coordinate
=
R + v0 cos θ=
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