Magnetic field due to currentHard

Question

Two long conductors are arranged as shown above to form overlapping cylinders, each of radius r, whose centers are separated by a distance d. Current of density J flows into the plane of the page along the shaded part of one conductor and an equal current flows out of the plane of the page along the shaded portion of the other, as shown. What are the magnitude and direction of the magnetic field at point A ?
                                                

Options

A.πdJ, in the +y-direction
B., in the +y direction
C., in the +y direction
D., in the +y direction

Solution

Ampere′s Law ⇒ B2π = π0J
B = ∴ Bnet = 2B = πdJĵ

Create a free account to view solution

View Solution Free
Topic: Magnetic field due to current·Practice all Magnetic field due to current questions

More Magnetic field due to current Questions

Force between straight wire and loop will be :-...Electron of mass m and charge q is travelling with a speed v along a circular path of radius r at right angles to a unif...A mass spectrometer is a device which select particle of equal mass. An iron with electric charge q > 0 starts at res...When alternating current passes through a spring then it :-...Net magnetic field at the centre of the circle O due to a current carrying loop as shown in figure is (θ < 108o)...