Magnetic field due to currentHard
Question
A block of mass m & charge q is released on a long smooth inclined plane magnetic filed B is constant, uniform, horizontal and parallel to surface as shown. Find the time from start when block loses contact with the surface
Options
A.
B.
C.
D.None
Solution
v = (g sinθ)t
N = mg cosθ - qvB = 0 ⇒ t = mcotθ/qB
N = mg cosθ - qvB = 0 ⇒ t = mcotθ/qB
Create a free account to view solution
View Solution FreeMore Magnetic field due to current Questions
A 250-Turn rectangular coil of length 2.1 cm and width 1.25 cm carries a current of 85 μA and subjected to magnetic...The magnetic field due to a current carrying circular loop of radius 3 cm at a point on the axis at a distance of 4 cm f...A wire carrying current I has the shape as shown in adjoining figure. Linear parts of the wire are very long and paralle...Find the magnitude and direction of a force vector acting on a unit length of a thin wire, carrying a current I = 8.0A, ...Wtres 1 and 2 carryingcurring i1 and i2 respectively are inclined at an angle θ to each other. What is the force on...