Magnetic field due to currentHard
Question
A block of mass m & charge q is released on a long smooth inclined plane magnetic filed B is constant, uniform, horizontal and parallel to surface as shown. Find the time from start when block loses contact with the surface
Options
A.
B.
C.
D.None
Solution
v = (g sinθ)t
N = mg cosθ - qvB = 0 ⇒ t = mcotθ/qB
N = mg cosθ - qvB = 0 ⇒ t = mcotθ/qB
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