Magnetic field due to currentHard
Question
Two particles, each of mass m and charge q, are attached to ends of a light rigid rod of length 2R. The rod is rotated at a constant angular speed about a perpendicular axis passing through its centre. The ratio of the magnitude of the magnetic moment of the system and its angular momentum about the centre of the rod is
Options
A.q/2m
B.q/m
C.2q/m
D.2/πm
Solution
Current, i = (frequency) (charge)
Mangetic moment,
M = (i)(A) =
(πR2) = (qωR2)Angulae momentum,
L = 2Iω = 2(mR2)ω
∴
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