Magnetic field due to currentHard
Question
A particle of charge -16 × 10-18 C moving with velocity 10 ms-1 along the x-axis enters region where a magnetic field of induction B is along the y-axis and an electric field of magnitude 104 V / m is along the negative z-axis If the charged particle continues moving along the x-axis, the magnitude of B is -
Options
A.103 Wb/m2
B.105 Wb/m2
C.1016 Wb/m2
D.10-3 Wb/m2
Solution
= q(
× 
+ 
) = 0 ⇒ q (10î × Bĵ - 104
) = 0⇒ B = 103 Wb/,2
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