Magnetic field due to currentHard
Question
In a vibration magnetometer, the time period of a bar magnet oscillating in horizontal component of earth′s magnetic field H is 2 second. When a magnet is brought near and parallel to it, the time period reduces to 1 second. The ratio F/H of the field F due to magnet and the horizontal component H, will be : -
Options
A.3
B.1/3
C.√3
D.1/√3
Solution
T = 2π 
... (i)
T′ = 2π
... (ii)
by equation (i) and (ii)
... (iii)
by solving equation (iii) F = 3H ⇒
= 3
... (i)T′ = 2π
... (ii)by equation (i) and (ii)
... (iii)by solving equation (iii) F = 3H ⇒
= 3Create a free account to view solution
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