MagnetismHard
Question
Figure shows a square current carrying loop ABCD of side 10 cm and current i = 10 A. The magnetic moment 
of the loop is
of the loop isOptions
A.(0.05) (î - √3
) A - m2
) A - m2B.(0.05) (ĵ + ) A - m2
) A - m2C.(0.05) (√3î + ) A - m2
) A - m2D.(î + ) A - m2
) A - m2Solution
= MIA
= 1 × 10 × 0.1 (î cos 60o -
cos30o)= 0.05 (î - √3
) A - m2Create a free account to view solution
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