GravitationHard
Question
A cavity of radius R/2 is made inside a solid sphere of radius R. The centre of the cavity is located at a distance R/2 from the centre of the sphere. The gravitational force on a particle of mass ′m′ at a distance R/2 from the centre of the sphere on the joining both the centre of sphere and cavity is (opposite to the centre of cavity).
[Here g = GM/R2, where M is the mass of the sphere]
[Here g = GM/R2, where M is the mass of the sphere]
Options
A.
B.
C.
D.None of these
Solution
Fnet = force due for sphere + force due for cavity
=
+ 0 ⇒ 
=
+ 0 ⇒ Create a free account to view solution
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