Chemical BondingHard
Question
The correct order of the following species the central atom has the type of hybridization which is not the same as that present in the other three ?
Options
A.SF4
B.I3-
C.SbCl52-
D.PCl5
Solution
Molecules having the same number of hybrid orbitals, have same hybridization and number of hybrid orbitals,
H = 1/2 [V + X - C + A]
where, V = no. of valence electrons of central atom
X = no. of monovalent atoms
C = charge on cation
A = charge on anion.
(a) In SF4,
H = 1/2 [6 + 4 - 0 + 0] = 5
(b) In I3-,
H = 1/2 [7 + 2 + 1] = 5
(c) In SbCl52-,
H = 1/2 [5 + 5 + 2] = 6
(d) In PCl5,
H = 1/2 [5 + 5 + 0 - 0] = 5
Since, only SbCl52- has different number of hybrid orbitals (ie, 6) from the other given species, its hybridization is different from the other, ie, sp3d2. (The hybridization of other spices is sp3d)
H = 1/2 [V + X - C + A]
where, V = no. of valence electrons of central atom
X = no. of monovalent atoms
C = charge on cation
A = charge on anion.
(a) In SF4,
H = 1/2 [6 + 4 - 0 + 0] = 5
(b) In I3-,
H = 1/2 [7 + 2 + 1] = 5
(c) In SbCl52-,
H = 1/2 [5 + 5 + 2] = 6
(d) In PCl5,
H = 1/2 [5 + 5 + 0 - 0] = 5
Since, only SbCl52- has different number of hybrid orbitals (ie, 6) from the other given species, its hybridization is different from the other, ie, sp3d2. (The hybridization of other spices is sp3d)
Create a free account to view solution
View Solution FreeMore Chemical Bonding Questions
Hg(NO3)2 W + X + O2X + H2O → NHO2 HNO3...The tendency of BF3, BCl3 and BBr3 to behave as Lewis acid decreases in the sequence...In which of the following arrangements the given sequence is not strictly according to the property indicated against it...The correct stability order for the following species is...The molecule which has zero dipole moment is :...