Chemical BondingHard
Question
The correct order of the following species the central atom has the type of hybridization which is not the same as that present in the other three ?
Options
A.SF4
B.I3-
C.SbCl52-
D.PCl5
Solution
Molecules having the same number of hybrid orbitals, have same hybridization and number of hybrid orbitals,
H = 1/2 [V + X - C + A]
where, V = no. of valence electrons of central atom
X = no. of monovalent atoms
C = charge on cation
A = charge on anion.
(a) In SF4,
H = 1/2 [6 + 4 - 0 + 0] = 5
(b) In I3-,
H = 1/2 [7 + 2 + 1] = 5
(c) In SbCl52-,
H = 1/2 [5 + 5 + 2] = 6
(d) In PCl5,
H = 1/2 [5 + 5 + 0 - 0] = 5
Since, only SbCl52- has different number of hybrid orbitals (ie, 6) from the other given species, its hybridization is different from the other, ie, sp3d2. (The hybridization of other spices is sp3d)
H = 1/2 [V + X - C + A]
where, V = no. of valence electrons of central atom
X = no. of monovalent atoms
C = charge on cation
A = charge on anion.
(a) In SF4,
H = 1/2 [6 + 4 - 0 + 0] = 5
(b) In I3-,
H = 1/2 [7 + 2 + 1] = 5
(c) In SbCl52-,
H = 1/2 [5 + 5 + 2] = 6
(d) In PCl5,
H = 1/2 [5 + 5 + 0 - 0] = 5
Since, only SbCl52- has different number of hybrid orbitals (ie, 6) from the other given species, its hybridization is different from the other, ie, sp3d2. (The hybridization of other spices is sp3d)
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