JEE Advanced | 2013CircleHard

Question

Circle(s) touching x-axis at a distance 3 from the origin and having an intercept of length or y-axis is (are)

Options

A.x2 + y2 - 6x + 8y + 9 = 0
B.x2 + y2 - 6x + 7y + 9 = 0
C.x2 + y2 - 6x - 8y + 9 = 0
D.x2 + y2 - 6x - 7y + 9 = 0

Solution


                

As per figure,
R2 = 32 +
∴ centre ≡ (3,4) radius 4
∴equation x2 + y2 - 6x - 8y + 9 = 0 such a circle can lie in all 4 quadrants as shown in figure.
∴ equation can be x2 + y2 6x 8y + 9 = 0

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