CircleEasy
Question
If the lines 2x + 3y + 1 = 0 and 3x - y - 4 = 0 lie along diameters of a circle of circumference 10π, then the equation of the circle is
Options
A.x2 + y2 - 2x + 2y - 23 = 0
B.x2 + y2 - 2x - 2y - 23 = 0
C.x2 + y2 + 2x + 2y - 23 = 0
D.x2 + y2 + 2x - 2y - 23 = 0
Solution
Intersection of given lines is the centre of the circle i.e. (1, - 1)
Circumference = 10π ⇒ radius r = 5
⇒ equation of circle is x2 + y2 - 2x + 2y - 23 = 0.
Circumference = 10π ⇒ radius r = 5
⇒ equation of circle is x2 + y2 - 2x + 2y - 23 = 0.
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