GravitationHard
Question
A body attains a height equal to the radius of the Earth when projected from Earth′ surface. The velocity of the body with which it was projected is : -
Options
A.
B.
C.
D.
Solution
By applying conservation of energy
KEi + PEi = KEf + PEf
mv2 - 
mv2 = 
mv2 =
⇒ u = 
KEi + PEi = KEf + PEf
Create a free account to view solution
View Solution FreeMore Gravitation Questions
Net gravitational force at the centre of a square is found to be $F_{1}$ when four particles having mass $M,2M,3M$ and $...The magnitudes of gravitational field at distance r1 and r2 from the centre of a uniform sphere of radius R and mass M a...A small ball of mass ′m′ is released at a height ′R′ above the Earth surface, as shown in the fi...A solid sphere of uniform density and radius 4 units is located with its centre at the origin O of coordinates. Two sphe...The escape velocity for a planet is ve. A tunnel is dug along the diameter of the planet and a small body is dropped int...