GravitationHard
Question
If the gravitational force were to vary inversely-as mth power of the distance, then the time period of a planet in circular orbit of radius r around the Sun will be proportional to
Options
A.r-3m/2
B.r3m/2
C.rm+1/2
D.r(m+1)/2
Solution
F ∝
; F = 
This force will provide the required centripetal force
Therefore
mω2 r =
; ω2 = 
T =
⇒ T ∝ r(m+1)/2
This force will provide the required centripetal force
Therefore
mω2 r =
T =
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