NEETGaseous StateHard
Question
A 40 ml of a mixture of H2 and O2 at 18oC and 1 atm pressure was sparked so that the formation of water was complete. The remaining pure gas had a volume of 10 ml at 18oC and 1 atm pressure. If the remaining gas was H2, the mole fraction of H2 in the 40 ml mixture is :
Options
A.0.75
B.0.5
C.0.65
D.0.85
Solution
H2 +1/2O2 → H2O(l)
a b 0
a-2b 0 b
Reaction is studied at constant P &T
a+b = 40 a-2b = 10
a = 30 ml b = 10ml
mole fraction of H2 = volume fraction of H2 =30/40 = 0.75.
a b 0
a-2b 0 b
Reaction is studied at constant P &T
a+b = 40 a-2b = 10
a = 30 ml b = 10ml
mole fraction of H2 = volume fraction of H2 =30/40 = 0.75.
Create a free account to view solution
View Solution FreeMore Gaseous State Questions
Which of the following compounds show sulimation ?...2 litres of moist hydrogen were collected over water at 26oC at a total pressure of one atmosphere. On analysis, it was ...A real gas obeying Vander Waal′s equation will resemble ideal gas, if the :...When CO2 under high pressure is released from a fire extinguisher, particles of solid CO2 are formed, despite the low su...Helium atom is two times heavier than a hydrogen molecule. At 298 K, the average kinetic energy of a helium atom is...