Sound WavesHard
Question
An open pipe is suddenly closed at one end with the result that the frequency of third harmonic of the closed pipe is found to be higher by 100 Hz than the fundamental frequency of the open pipe. The fundamental frequency of the open pipe is : -
Options
A.200 Hz
B.300 Hz
C.240 Hz
D.480 Hz
Solution
f1λ1 = v
f1
= v ⇒ f1 = 
; f2(2L) = v ⇒ f2 = 
Given that f1 - f2 = 100
⇒
= 100 ⇒
= 200 Hz
f1
= v ⇒ f1 = ; f2(2L) = v ⇒ f2 = Given that f1 - f2 = 100
⇒
= 100 ⇒ = 200 HzCreate a free account to view solution
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