Sound WavesHard
Question
A steel wire of length 60 cm and area of cross-section 10-6 m2 is joined with an aluminum wire of length 45 cm and area of cross-section 3 × 10-6m2. The composite string is stretched by tension of 80 N. Density of steel is 7800 kg m-3 and that of aluminum is 2600 kg m-3. The minimum frequency of tuning fork which can produce standing wave in it with node at the joint is : -
Options
A.357. 3 Hz
B.375 . 3 Hz
C.337 . 5 Hz
D.325.5 Hz
Solution
f1 = f2 (m → no. of loops in steel wire n → no. of loops in aluminum wire)
⇒
⇒
⇒
(minimum)
⇒ f =
= 337.5Hz
⇒
⇒
⇒
(minimum)⇒ f =
= 337.5HzCreate a free account to view solution
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