Gaseous StateHard
Question
The rate of diffusion of 2 gases ′A′ and ′B′ are in the ratio 16: 3. If the ratio of their masses present in the mixture is 2 : 3. Then
Options
A.The ratio of their molar masses is 16 : 1
B.The ratio of their molar masses is 1 : 4
C.The ratio of their moles present inside the container is 1 : 24
D.The ratio of their moles present inside the container is 8 : 3
Solution
Given 
we have
=
⇒ 
= 8
⇒
= 4
∴ mole ratio =
we have
=
⇒ = 8⇒
= 4∴ mole ratio =
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