Sound WavesHard

Question

A standing wave is created on a string of length 120 m and it is vibrating in 6th harmonic. Maximum possible amplitude of any particle is 10 cm and maximum possible velocity will be 10 cm/s. Choose the correct statement.

Options

A.Angular wave number of two waves will be .
B.Time period of any particle’s SHM will be 4π sec.
C.Any particle will have same kinetic energy as potential energy.
D.Amplitude of interfering waves are 10 cm each.

Solution

= 120 ⇒ λ = 40 ⇒ k = ⇒ Aω = vmax ⇒ ω = 1 ⇒ T = 2π

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