Sound WavesHard
Question
A person speaking normally produces a sound intensity of 40 dB at a distance of 1m. If the threshold intensity for reasonable audibility is20 dB, the max. distance at which he can be heard clearly is :-
Options
A.4 m
B.5m
C.10 m
D.20 m
Solution
40 = 10 log10 
= 104
I0 = 10-12 wm-2
20 = 10 log10
= 102
⇒ r2 = 10 m (∵ r1 = 1m)]
= 104I0 = 10-12 wm-2
20 = 10 log10
= 102 ⇒ r2 = 10 m (∵ r1 = 1m)]Create a free account to view solution
View Solution FreeMore Sound Waves Questions
The velosity of sound in a gas pressure P and density d is...The intensity of sound 10 m from a tornado siren is a very loud 130 db. At what distance would you need to be for the in...A larga horizontal surface moves up and down in S.H.M with an amplitude of 1cm. If a mass of 10 kg (which is plased on t...Choose correct statement?...A wave is propagating along x-axis. The displacement of particle of the medium in z- direction at t = 0 is given by : z ...