SHMHard
Question
The displacement - time graph of particle executing SHM is shown.
Which of the following statements is / are true?
Which of the following statements is / are true?
Options
A.The velocity is maximum at t = T/2
B.The velocity is maximum at t = T
C.The force is zero at t = 3T/4
D.The potential energy equals the oscillation energy at T/2.
Solution
∵ a = - ω2y and at t = T, y maximum so acceleration is maximum at t.
Also y = 0 at t =
, so force is zero at t = 
At t =
, v = 0 ⇒ PE = oscillation energy
Also y = 0 at t =
, so force is zero at t = At t =
, v = 0 ⇒ PE = oscillation energyCreate a free account to view solution
View Solution FreeMore SHM Questions
A single of 5 kHz frequency is amplitude modulated on a carrier wave of frequency 2 MHz. The frequencies of the resultan...For a particle executing simple harmonic motion, the acceleration is proportional to...The displacement of a particle in S.H.M. is x = a sinωt. Which of the following graph between displacement and time...The magnitude of average acceleration in half time period from equilibrium position in a simple harmonic motion is...A particle performs S.H.M. of amplitude A with angular frequency ω along a straight line. When it is at a distance ...