SHMHard

Question

The displacement - time graph of particle executing SHM is shown.

Which of the following statements is / are true?

Options

A.The velocity is maximum at t = T/2
B.The velocity is maximum at t = T
C.The force is zero at t = 3T/4
D.The potential energy equals the oscillation energy at T/2.

Solution

∵ a = - ω2y and at t = T, y maximum so acceleration is maximum at t.
Also y = 0 at t = , so force is zero at t =
At t = , v = 0 ⇒ PE = oscillation energy

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